Sanakey
5 天以前 2af71bcf522c485ea005184c977986374a7dcc4a
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const queryString = window.location.search; // 获取 ? 后面的字符串
const params = new URLSearchParams(queryString);
 
const emailParam = params.toString(); // 获取整个查询部分的字符串
console.log(emailParam); // 输出 1244041895@qq.com=test@example.com